-12a+1+36a^2=0

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Solution for -12a+1+36a^2=0 equation: 



-12a+1+36a^2=0

a = 36; b = -12; c = +1;
Δ = b2-4ac
Δ = -122-4·36·1
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$a=\frac{-b}{2a}=\frac{12}{72}=1/6$

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